$physics 9702 diffraction of a wave$

That's why I said W and X can be considered to be the same. So, it's as if that wire is not even there. If you look carefully, you will see that no component is connected between the bold dot and the right end of the potentiometer. If what you said is correct, then the potentiometer is contributing all its resistances or the potentiometer is just like a fixed resisor. Be sure to understand that a potentiometer is not like a fixed resistor. So, even if it's connected, it is not contributing any resistances. In all of them, the junction up to the right end are not contributing. Like I said, the left end up to the junction contributes. Noise reduction headphones actively produce their own sound waves in order to cancel out external sound waves. Reference: Past Exam Paper – June 2013 Paper 11 Q29

$physics 9702 diffraction of a wave$

What is the phase difference between external sound wave and wave produced Then produces wave of that frequency but of a different phase. Microphone in headphones receives waves of one frequency. Noise reduction headphones actively produce their own sound waves in order

$physics 9702 diffraction of a wave$

Resistance in the circuit is not the same as in W or X. Through it and instead, current flows through the slider. Theīold point and the slider (head of arrow) are at the same potential and theįixed resistor is connected between these 2 points. The reason is similar to the circuit in X. Then along a distance d on the potentiometer but here, the current does notįlow through the fixed resistor. Even if theĬircuit is complete, the results obtained on a graph would not be identical toįor arrangement Z, current flows from the positive terminal of the battery, So, this arrangement is different from those of W and X. Than the distance d on the wire of the potentiometer is connected to theĬircuit.

$physics 9702 diffraction of a wave$

Physics 9702 diffraction of a wave